1x^2-500x+50000=0

Solution for 1x^2-500x+50000=0 equation:

1x^2-500x+50000=0

We add all the numbers together, and all the variables

x^2-500x+50000=0

a = 1; b = -500; c = +50000;
Δ = b2-4ac
Δ = -5002-4·1·50000
Δ = 50000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50000}=\sqrt{10000*5}=\sqrt{10000}*\sqrt{5}=100\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-100\sqrt{5}}{2*1}=\frac{500-100\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+100\sqrt{5}}{2*1}=\frac{500+100\sqrt{5}}{2}
$